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18x^2-57x-60=0
a = 18; b = -57; c = -60;
Δ = b2-4ac
Δ = -572-4·18·(-60)
Δ = 7569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7569}=87$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-87}{2*18}=\frac{-30}{36} =-5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+87}{2*18}=\frac{144}{36} =4 $
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